7t^2+4t/7t^2+8=1

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Solution for 7t^2+4t/7t^2+8=1 equation: 



7t^2+4t/7t^2+8=1

We move all terms to the left:

7t^2+4t/7t^2+8-(1)=0



Domain of the equation: 7t^2!=0

t^2!=0/7

t^2!=√0

t!=0

t∈R



We add all the numbers together, and all the variables

7t^2+4t/7t^2+7=0

We multiply all the terms by the denominator


7t^2*7t^2+4t+7*7t^2=0

Wy multiply elements

49t^4+49t^2+4t=0

We do not support etpression: t^4

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